36x^2+96x+64=96x+68

Solution for 36x^2+96x+64=96x+68 equation:

36x^2+96x+64=96x+68

We move all terms to the left:

36x^2+96x+64-(96x+68)=0

We get rid of parentheses

36x^2+96x-96x-68+64=0

We add all the numbers together, and all the variables

36x^2-4=0

a = 36; b = 0; c = -4;
Δ = b2-4ac
Δ = 02-4·36·(-4)
Δ = 576
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{576}=24$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-24}{2*36}=\frac{-24}{72}
=-1/3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+24}{2*36}=\frac{24}{72}
=1/3
$